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[Python] 실패율

def solution(N, stages): fail = {} success = len(stages) for i in range(1, N+1) : if i not in stages : fail[i] = 0 continue else : stop = stages.count(i) fail[i] = stop/success success -= stop return sorted(fail, key=lambda x : fail[x], reverse=True) 풀이 1) stages에 없는 단계(실패율 0) 저장 fail = {} success = len(stages) for i in range(1, N+1) : if i not in stages : fail[i] = 0 continue ① i 단계가 실패율이 '얼마' ..

Algorithm/Programmers 2021.05.02
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Dijkstra, BFS, stack, 파이썬, programmers, binary, Queue, Two Pointer, binary search, Python, dp, swea, BOJ, greedy, Backtracking, Spring, dfs, java, 프로그래머스, 자바,

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